.Where does the extra exposure go when planets and their rotational horizon are totally outmatched by their stars size……….applications in flying cars

.Where does the extra exposure go when planets and their rotational horizon

are totally outmatched by their stars size

by Henryk Szubinski

.

.

.

long time ago the SIZE of envelopement of SIZE relations of the sun with its planets might have seemed complex

nowadays the answer to size is DIRECTLY supported with images from space that show the real size of STARS and their planets.

this makes the answer easy when looking at the small Earth in relation to the sun.

So that the obvious answer is that the frontal HORIZONS are almost exactly MATCHED to each each other.

.

.

the x 1280 size of the sun ,then defines the total gravity between 2 objects

as the largest star with the smallest planet

so that the gravity is related to the larger universe as the remains of the 1 super star

BEING THE SIZE OF THE UNIVERSE AND THE

size of the exposure being directly computatable as the missing value = gravity of the universe

what occurs is that the planet is reduced into one atom

As being related to the STILLNESS of the sun in its moment of highest power.

Wherein the atom remaning will displace through any He + linked by any H+

so that the resultance is the seperation of the

He+ from the H+ by the atom remaining of the star system

=extra seperation of the He+ from the H+

where the vector seperation = S /g

This is like reversing the evolution of the UNIVERSE by about

1/ 10 x to the 200

in length that seperates its basis of H+ and He+

.

the interval state of the OBSCURITY between spacetime and its opposite

is the basis of expansion OUT and contraction back

so that the FLEXATION character is representative of the

atomic bond being used in reduceing the seperation as keeping it to minimal

vectors that are otherwise in BONDS between atoms

using the gravity warp in flying cars